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# IVLE - Informatics Virtual Learning Environment
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# Copyright (C) 2007-2008 The University of Melbourne
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
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# Script: serveservice
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# Author: Thomas Conway
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# A CGI script for serving files.
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from ivle import (cgirequest, studpath)
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from ivle import zip as zipmod
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req = cgirequest.CGIRequest()
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req.install_error_handler()
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# Work out the parts of the URL
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url = urlparse.urlparse(req.path)
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filename = studpath.url_to_jailpaths(urlpath)[2]
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default_mimetype = "application/octet-stream"
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zip_mimetype = "application/zip"
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# If any "path=" variables have been supplied, bring these into a list and
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# make a zip file instead.
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fields = req.get_fieldstorage()
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paths = fields.getlist("path")
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zipbasepath = filename
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zipfilename = os.path.basename(zipbasepath)
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#for i in range(0, len(paths)):
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#paths[i] = paths[i].value
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req.throw_error(req.HTTP_NOT_FOUND,
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"The path specified is invalid.")
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elif not os.access(filename, os.R_OK):
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req.throw_error(req.HTTP_NOT_FOUND,
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"The specified file (%s) does not exist." % urlpath)
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# If it's a directory, serve as a zip file
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if os.path.isdir(filename):
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# Zip it from the perspective of its own parent.
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# That way it will be a directory in the top level of the zip
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if filename[-1] == os.sep: filename = filename[:-1]
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splitpath = filename.rsplit(os.sep, 1)
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if len(splitpath) == 1:
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zipbasepath = splitpath[0]
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paths = [splitpath[1]]
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zipfilename = paths[0]
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req.content_type = zip_mimetype
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# zipfilename is some filename. Strip trailing slash or extension,
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elif zipfilename[-1] == '/':
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zipfilename = zipfilename[:-1]
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elif '.' in zipfilename:
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zipfilename = zipfilename[:zipfilename.rindex('.')]
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req.headers_out["Content-Disposition"] = ("attachment; filename=" +
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zipfile = StringIO.StringIO()
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zipmod.make_zip(zipbasepath, paths, zipfile)
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req.write(zipfile.getvalue())
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#req.content_type = default_mimetype
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req.sendfile(filename)