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1
by brian
clean slate |
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DROP TABLE IF EXISTS t1, t2;
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CREATE TABLE t1 (
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id INTEGER NOT NULL PRIMARY KEY AUTO_INCREMENT,
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gender CHAR(1),
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name VARCHAR(20)
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);
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SELECT SUM(DISTINCT LENGTH(name)) s1 FROM t1;
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s1
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NULL
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INSERT INTO t1 (gender, name) VALUES (NULL, NULL);
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INSERT INTO t1 (gender, name) VALUES (NULL, NULL);
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INSERT INTO t1 (gender, name) VALUES (NULL, NULL);
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SELECT SUM(DISTINCT LENGTH(name)) s1 FROM t1;
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s1
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NULL
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INSERT INTO t1 (gender, name) VALUES ('F', 'Helen'), ('F', 'Anastasia'),
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('F', 'Katherine'), ('F', 'Margo'), ('F', 'Magdalene'), ('F', 'Mary');
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CREATE TABLE t2 SELECT name FROM t1;
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SELECT (SELECT SUM(DISTINCT LENGTH(name)) FROM t1) FROM t2;
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(SELECT SUM(DISTINCT LENGTH(name)) FROM t1)
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18
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18
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23 |
18
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24 |
18
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25 |
18
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26 |
18
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18
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18
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18
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DROP TABLE t2;
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INSERT INTO t1 (gender, name) VALUES ('F', 'Eva'), ('F', 'Sofia'),
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('F', 'Sara'), ('F', 'Golda'), ('F', 'Toba'), ('F', 'Victory'),
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('F', 'Faina'), ('F', 'Miriam'), ('F', 'Beki'), ('F', 'America'),
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('F', 'Susan'), ('F', 'Glory'), ('F', 'Priscilla'), ('F', 'Rosmary'),
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('F', 'Rose'), ('F', 'Margareth'), ('F', 'Elizabeth'), ('F', 'Meredith'),
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('F', 'Julie'), ('F', 'Xenia'), ('F', 'Zena'), ('F', 'Olga'),
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('F', 'Brunhilda'), ('F', 'Nataly'), ('F', 'Lara'), ('F', 'Svetlana'),
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('F', 'Grethem'), ('F', 'Irene');
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SELECT
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SUM(DISTINCT LENGTH(name)) s1,
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SUM(DISTINCT SUBSTRING(NAME, 1, 3)) s2,
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SUM(DISTINCT LENGTH(SUBSTRING(name, 1, 4))) s3
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FROM t1;
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s1 s2 s3
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42 0 7
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SELECT
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SUM(DISTINCT LENGTH(g1.name)) s1,
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SUM(DISTINCT SUBSTRING(g2.name, 1, 3)) s2,
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SUM(DISTINCT LENGTH(SUBSTRING(g3.name, 1, 4))) s3
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FROM t1 g1, t1 g2, t1 g3;
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s1 s2 s3
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42 0 7
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SELECT
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1487.1.1
by Brian Aker
There is room for improvement around this. We should be using rows as well |
54 |
SQL_BIG_RESULT
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1
by brian
clean slate |
55 |
SUM(DISTINCT LENGTH(g1.name)) s1,
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SUM(DISTINCT SUBSTRING(g2.name, 1, 3)) s2,
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SUM(DISTINCT LENGTH(SUBSTRING(g3.name, 1, 4))) s3
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FROM t1 g1, t1 g2, t1 g3 GROUP BY LENGTH(SUBSTRING(g3.name, 5, 10));
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s1 s2 s3
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42 0 NULL
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42 0 7
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42 0 4
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42 0 4
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42 0 4
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42 0 4
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42 0 4
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SELECT SQL_BUFFER_RESULT
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SUM(DISTINCT LENGTH(name)) s1,
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SUM(DISTINCT SUBSTRING(NAME, 1, 3)) s2,
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SUM(DISTINCT LENGTH(SUBSTRING(name, 1, 4))) s3
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FROM t1;
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s1 s2 s3
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42 0 7
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1487.1.1
by Brian Aker
There is room for improvement around this. We should be using rows as well |
74 |
SELECT SQL_BIG_RESULT
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1
by brian
clean slate |
75 |
SUM(DISTINCT LENGTH(g1.name)) s1,
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SUM(DISTINCT SUBSTRING(g2.name, 1, 3)) s2,
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SUM(DISTINCT LENGTH(SUBSTRING(g3.name, 1, 4))) s3
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FROM t1 g1, t1 g2, t1 g3 GROUP BY LENGTH(SUBSTRING(g3.name, 5, 10));
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s1 s2 s3
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42 0 NULL
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42 0 7
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42 0 4
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42 0 4
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42 0 4
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42 0 4
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42 0 4
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SET @l=1;
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UPDATE t1 SET name=CONCAT(name, @l:=@l+1);
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SELECT SUM(DISTINCT RIGHT(name, 1)) FROM t1;
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SUM(DISTINCT RIGHT(name, 1))
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45
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SELECT SUM(DISTINCT id) FROM t1;
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SUM(DISTINCT id)
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703
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SELECT SUM(DISTINCT id % 11) FROM t1;
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SUM(DISTINCT id % 11)
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55
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DROP TABLE t1;
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