~drizzle-trunk/drizzle/development

1 by brian
clean slate
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/* Copyright (C) 2000-2002, 2004 MySQL AB
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   This program is free software; you can redistribute it and/or modify
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   it under the terms of the GNU General Public License as published by
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   the Free Software Foundation; version 2 of the License.
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   This program is distributed in the hope that it will be useful,
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   but WITHOUT ANY WARRANTY; without even the implied warranty of
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   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
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   GNU General Public License for more details.
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   You should have received a copy of the GNU General Public License
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   along with this program; if not, write to the Free Software
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   Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA */
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/* functions on blocks; Keys and records are saved in blocks */
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#include "heapdef.h"
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/*
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  Find record according to record-position.
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  The record is located by factoring position number pos into (p_0, p_1, ...) 
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  such that
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     pos = SUM_i(block->level_info[i].records_under_level * p_i)
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  {p_0, p_1, ...} serve as indexes to descend the blocks tree.
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*/
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uchar *hp_find_block(HP_BLOCK *block, ulong pos)
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{
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  register int i;
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  register HP_PTRS *ptr; /* block base ptr */
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  for (i=block->levels-1, ptr=block->root ; i > 0 ; i--)
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  {
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    ptr=(HP_PTRS*)ptr->blocks[pos/block->level_info[i].records_under_level];
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    pos%=block->level_info[i].records_under_level;
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  }
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  return (uchar*) ptr+ pos*block->recbuffer;
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}
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/*
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  Get one new block-of-records. Alloc ptr to block if needed
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  SYNOPSIS
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    hp_get_new_block()
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      block             HP_BLOCK tree-like block
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      alloc_length OUT  Amount of memory allocated from the heap
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  Interrupts are stopped to allow ha_panic in interrupts 
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  RETURN
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    0  OK
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    1  Out of memory
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*/
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int hp_get_new_block(HP_BLOCK *block, size_t *alloc_length)
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{
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  register uint i,j;
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  HP_PTRS *root;
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  for (i=0 ; i < block->levels ; i++)
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    if (block->level_info[i].free_ptrs_in_block)
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      break;
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  /*
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    Allocate space for leaf block plus space for upper level blocks up to
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    first level that has a free slot to put the pointer. 
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    In some cases we actually allocate more then we need:
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    Consider e.g. a situation where we have one level 1 block and one level 0
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    block, the level 0 block is full and this function is called. We only 
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    need a leaf block in this case. Nevertheless, we will get here with i=1 
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    and will also allocate sizeof(HP_PTRS) for non-leaf block and will never 
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    use this space.
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    This doesn't add much overhead - with current values of sizeof(HP_PTRS) 
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    and my_default_record_cache_size we get about 1/128 unused memory.
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   */
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  *alloc_length=sizeof(HP_PTRS)*i+block->records_in_block* block->recbuffer;
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  if (!(root=(HP_PTRS*) my_malloc(*alloc_length,MYF(MY_WME))))
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    return 1;
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  if (i == 0)
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  {
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    block->levels=1;
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    block->root=block->level_info[0].last_blocks=root;
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  }
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  else
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  {
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    if ((uint) i == block->levels)
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    {
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      /* Adding a new level on top of the existing ones. */
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      block->levels=i+1;
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      /*
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        Use first allocated HP_PTRS as a top-level block. Put the current
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        block tree into the first slot of a new top-level block.
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      */
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      block->level_info[i].free_ptrs_in_block=HP_PTRS_IN_NOD-1;
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      ((HP_PTRS**) root)[0]= block->root;
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      block->root=block->level_info[i].last_blocks= root++;
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    }
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    /* Occupy the free slot we've found at level i */
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    block->level_info[i].last_blocks->
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      blocks[HP_PTRS_IN_NOD - block->level_info[i].free_ptrs_in_block--]=
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	(uchar*) root;
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    /* Add a block subtree with each node having one left-most child */
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    for (j=i-1 ; j >0 ; j--)
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    {
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      block->level_info[j].last_blocks= root++;
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      block->level_info[j].last_blocks->blocks[0]=(uchar*) root;
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      block->level_info[j].free_ptrs_in_block=HP_PTRS_IN_NOD-1;
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    }
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    /* 
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      root now points to last (block->records_in_block* block->recbuffer)
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      allocated bytes. Use it as a leaf block.
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    */
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    block->level_info[0].last_blocks= root;
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  }
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  return 0;
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}
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	/* free all blocks under level */
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uchar *hp_free_level(HP_BLOCK *block, uint level, HP_PTRS *pos, uchar *last_pos)
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{
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  int i,max_pos;
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  uchar *next_ptr;
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  if (level == 1)
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    next_ptr=(uchar*) pos+block->recbuffer;
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  else
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  {
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    max_pos= (block->level_info[level-1].last_blocks == pos) ?
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      HP_PTRS_IN_NOD - block->level_info[level-1].free_ptrs_in_block :
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    HP_PTRS_IN_NOD;
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    next_ptr=(uchar*) (pos+1);
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    for (i=0 ; i < max_pos ; i++)
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      next_ptr=hp_free_level(block,level-1,
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			      (HP_PTRS*) pos->blocks[i],next_ptr);
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  }
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  if ((uchar*) pos != last_pos)
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  {
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    my_free((uchar*) pos,MYF(0));
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    return last_pos;
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  }
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  return next_ptr;			/* next memory position */
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}