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/* Copyright (C) 2000 MySQL AB
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; version 2 of the License.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program; if not, write to the Free Software
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Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA */
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str2int(src, radix, lower, upper, &val)
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converts the string pointed to by src to an integer and stores it in
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val. It skips leading spaces and tabs (but not newlines, formfeeds,
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backspaces), then it accepts an optional sign and a sequence of digits
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in the specified radix. The result should satisfy lower <= *val <= upper.
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The result is a pointer to the first character after the number;
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trailing spaces will NOT be skipped.
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If an error is detected, the result will be NullS, the value put
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in val will be 0, and errno will be set to
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EDOM if there are no digits
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ERANGE if the result would overflow or otherwise fail to lie
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within the specified bounds.
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Check that the bounds are right for your machine.
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This looks amazingly complicated for what you probably thought was an
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easy task. Coping with integer overflow and the asymmetric range of
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twos complement machines is anything but easy.
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So that users of atoi and atol can check whether an error occured,
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I have taken a wholly unprecedented step: errno is CLEARED if this
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#include <my_global.h>
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#include "my_sys.h" /* defines errno */
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#define char_val(X) (X >= '0' && X <= '9' ? X-'0' :\
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X >= 'A' && X <= 'Z' ? X-'A'+10 :\
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X >= 'a' && X <= 'z' ? X-'a'+10 :\
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char *str2int(register const char *src, register int radix, long int lower,
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long int upper, long int *val)
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int sign; /* is number negative (+1) or positive (-1) */
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int n; /* number of digits yet to be converted */
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long limit; /* "largest" possible valid input */
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long scale; /* the amount to multiply next digit by */
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long sofar; /* the running value */
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register int d; /* (negative of) next digit */
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int digits[32]; /* Room for numbers */
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/* Make sure *val is sensible in case of error */
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/* Check that the radix is in the range 2..36 */
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if (radix < 2 || radix > 36) {
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/* The basic problem is: how do we handle the conversion of
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a number without resorting to machine-specific code to
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check for overflow? Obviously, we have to ensure that
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no calculation can overflow. We are guaranteed that the
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"lower" and "upper" arguments are valid machine integers.
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On sign-and-magnitude, twos-complement, and ones-complement
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machines all, if +|n| is representable, so is -|n|, but on
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twos complement machines the converse is not true. So the
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"maximum" representable number has a negative representative.
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Limit is set to min(-|lower|,-|upper|); this is the "largest"
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number we are concerned with. */
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/* Calculate Limit using Scale as a scratch variable */
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if ((limit = lower) > 0) limit = -limit;
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if ((scale = upper) > 0) scale = -scale;
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if (scale < limit) limit = scale;
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/* Skip leading spaces and check for a sign.
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Note: because on a 2s complement machine MinLong is a valid
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integer but |MinLong| is not, we have to keep the current
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converted value (and the scale!) as *negative* numbers,
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so the sign is the opposite of what you might expect.
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while (my_isspace(&my_charset_latin1,*src)) src++;
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if (*src == '+') src++; else
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if (*src == '-') src++, sign = 1;
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/* Skip leading zeros so that we never compute a power of radix
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in scale that we won't have a need for. Otherwise sticking
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enough 0s in front of a number could cause the multiplication
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to overflow when it neededn't.
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while (*src == '0') src++;
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/* Move over the remaining digits. We have to convert from left
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to left in order to avoid overflow. Answer is after last digit.
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for (n = 0; (digits[n]=char_val(*src)) < radix && n < 20; n++,src++) ;
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/* Check that there is at least one digit */
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/* The invariant we want to maintain is that src is just
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to the right of n digits, we've converted k digits to
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sofar, scale = -radix**k, and scale < sofar < 0. Now
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if the final number is to be within the original
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Limit, we must have (to the left)*scale+sofar >= Limit,
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or (to the left)*scale >= Limit-sofar, i.e. the digits
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to the left of src must form an integer <= (Limit-sofar)/(scale).
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In particular, this is true of the next digit. In our
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incremental calculation of Limit,
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IT IS VITAL that (-|N|)/(-|D|) = |N|/|D|
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for (sofar = 0, scale = -1; --n >= 1;)
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if ((long) -(d=digits[n]) < limit) {
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limit = (limit+d)/radix, sofar += d*scale; scale *= radix;
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if ((long) -(d=digits[n]) < limit) /* get last digit */
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/* Now it might still happen that sofar = -32768 or its equivalent,
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so we can't just multiply by the sign and check that the result
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is in the range lower..upper. All of this caution is a right
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pain in the neck. If only there were a standard routine which
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says generate thus and such a signal on integer overflow...
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But not enough machines can do it *SIGH*.
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if (sofar < -LONG_MAX || (sofar= -sofar) > upper)
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else if (sofar < lower)
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errno=0; /* indicate that all went well */
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/* Theese are so slow compared with ordinary, optimized atoi */
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int atoi(const char *src)
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str2int(src, 10, (long) INT_MIN, (long) INT_MAX, &val);
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long atol(const char *src)
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str2int(src, 10, LONG_MIN, LONG_MAX, &val);
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#endif /* WANT_OUR_ATOI */