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/* - mode: c; c-basic-offset: 2; indent-tabs-mode: nil; -*-
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* vim:expandtab:shiftwidth=2:tabstop=2:smarttab:
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* Copyright (C) 2008 Sun Microsystems, Inc.
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* This program is free software; you can redistribute it and/or modify
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* it under the terms of the GNU General Public License as published by
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* the Free Software Foundation; either version 2 of the License, or
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* (at your option) any later version.
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* This program is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU General Public License for more details.
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* You should have received a copy of the GNU General Public License
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* along with this program; if not, write to the Free Software
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* Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
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* Common functions for dealing with calendrical calculations
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#if TIME_WITH_SYS_TIME
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# include <sys/time.h>
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# include <sys/time.h>
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#include "drizzled/calendar.h"
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/** Static arrays for number of days in a month and their "day ends" */
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static const uint32_t __leap_days_in_month[12]= {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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static const uint32_t __normal_days_in_month[12]= {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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static const uint32_t __leap_days_to_end_month[13]= {0, 31, 60, 91, 121, 151, 182, 213, 244, 274, 305, 335, 366};
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static const uint32_t __normal_days_to_end_month[13]= {0, 31, 59, 90, 120, 150, 181, 212, 243, 273, 304, 334, 365};
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* Private utility macro for enabling a switch between
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* Gregorian and Julian leap year date arrays.
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inline static const uint32_t* days_in_month(uint32_t y, enum calendar c)
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if (is_leap_year(y, c))
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return __leap_days_in_month;
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return __normal_days_in_month;
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inline static const uint32_t* days_to_end_month(uint32_t y, enum calendar c)
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if (is_leap_year(y, c))
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return __leap_days_to_end_month;
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return __normal_days_to_end_month;
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* Calculates the Julian Day Number from the year, month
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* and day supplied. The calendar used by the supplied
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* year, month, and day is assumed to be Gregorian Proleptic.
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* The months January to December are 1 to 12.
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* Astronomical year numbering is used, thus 1 BC is 0, 2 BC is −1,
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* and 4713 BC is −4712. In all divisions (except for JD) the floor
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* function is applied to the quotient (for dates since
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* March 1, −4800 all quotients are non-negative, so we can also
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* a = (14 - month) / 12
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* JDN = day + ((153m + 2) / 5) + 365y + (y / 4) - (y / 100) + (y / 400) - 32045
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* @cite http://en.wikipedia.org/wiki/Julian_day#Calculation
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* Year month and day values are assumed to be valid. This
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* method does no bounds checking or validation.
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* @param Month of date
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int64_t julian_day_number_from_gregorian_date(uint32_t year, uint32_t month, uint32_t day)
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int64_t a= (14 - month) / 12;
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int64_t y= year + 4800 - a;
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int64_t m= month + (12 * a) - 3;
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day_number= day + (((153 * m) + 2) / 5) + (365 * y) + (y / 4) - (y / 100) + (y / 400) - 32045;
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* Translates an absolute day number to a
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* Julian day number. Note that a Julian day number
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* is not the same as a date in the Julian proleptic calendar.
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* @param The absolute day number
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int64_t absolute_day_number_to_julian_day_number(int64_t absolute_day)
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return absolute_day + JULIAN_DAY_NUMBER_AT_ABSOLUTE_DAY_ONE;
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* Translates a Julian day number to an
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* absolute day number. Note that a Julian day number
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* is not the same as a date in the Julian proleptic calendar.
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* @param The Julian day number
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int64_t julian_day_number_to_absolute_day_number(int64_t julian_day)
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return julian_day - JULIAN_DAY_NUMBER_AT_ABSOLUTE_DAY_ONE;
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* Given a supplied Julian Day Number, populates a year, month, and day
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* with the date in the Gregorian Proleptic calendar which corresponds to
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* the given Julian Day Number.
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* @cite Algorithm from http://en.wikipedia.org/wiki/Julian_day
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* @param Julian Day Number
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* @param Pointer to year to populate
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* @param Pointer to month to populate
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* @param Pointer to the day to populate
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void gregorian_date_from_julian_day_number(int64_t julian_day
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, uint32_t *month_out
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int64_t j = julian_day + 32044;
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int64_t g = j / 146097;
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int64_t dg = j % 146097;
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int64_t c = (dg / 36524 + 1) * 3 / 4;
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int64_t dc = dg - c * 36524;
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int64_t b = dc / 1461;
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int64_t db = dc % 1461;
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int64_t a = (db / 365 + 1) * 3 / 4;
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int64_t da = db - a * 365;
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int64_t y = g * 400 + c * 100 + b * 4 + a;
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int64_t m = (da * 5 + 308) / 153 - 2;
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int64_t d = da - (m + 4) * 153 / 5 + 122;
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int64_t Y = y - 4800 + (m + 2) / 12;
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int64_t M = (m + 2) % 12 + 1;
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int64_t D = (int64_t)((double)d + 1.5);
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/* Push out parameters */
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*year_out= (uint32_t) Y;
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*month_out= (uint32_t) M;
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*day_out= (uint32_t) D;
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* Given a supplied Absolute Day Number, populates a year, month, and day
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* with the date in the Gregorian Proleptic calendar which corresponds to
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* the given Absolute Day Number.
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* @param Absolute Day Number
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* @param Pointer to year to populate
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* @param Pointer to month to populate
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* @param Pointer to the day to populate
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void gregorian_date_from_absolute_day_number(int64_t absolute_day
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, uint32_t *month_out
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gregorian_date_from_julian_day_number(
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absolute_day_number_to_julian_day_number(absolute_day)
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* Functions to calculate the number of days in a
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* particular year. The number of days in a year
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* depends on the calendar used for the date.
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* For the Julian proleptic calendar, a leap year
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* is one which is evenly divisible by 4.
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* For the Gregorian proleptic calendar, a leap year
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* is one which is evenly divisible by 4, and if
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* the year is evenly divisible by 100, it must also be evenly
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* Returns the number of days in a particular year
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* depending on the supplied calendar.
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* @param year to evaluate
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* @param calendar to use
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inline uint32_t days_in_year(const uint32_t year, enum calendar calendar)
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if (calendar == GREGORIAN)
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return days_in_year_gregorian(year);
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return days_in_year_julian(year);
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* Returns the number of days in a particular Julian calendar year.
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* @param year to evaluate
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inline uint32_t days_in_year_julian(const uint32_t year)
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/* Short-circuit. No odd years can be leap years... */
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return (year & 3) == 0;
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* Returns the number of days in a particular Gregorian year.
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* @param year to evaluate
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inline uint32_t days_in_year_gregorian(const uint32_t year)
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/* Short-circuit. No odd years can be leap years... */
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&& (year % 100 || ((year % 400 == 0) && year))
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* Returns the number of the day in a week.
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* Day Day Number Sunday first day?
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* -------------- ----------- -----------------
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* @param Julian Day Number
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* @param Consider Sunday the first day of the week?
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uint32_t day_of_week(int64_t day_number
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, bool sunday_is_first_day_of_week)
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uint32_t tmp= (uint32_t) (day_number % 7);
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/* 0 returned from above modulo is a Monday */
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if (sunday_is_first_day_of_week)
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tmp= (tmp == 6 ? 0 : tmp + 1);
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* Given a year, month, and day, returns whether the date is
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* valid for the Gregorian proleptic calendar.
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bool is_valid_gregorian_date(uint32_t year, uint32_t month, uint32_t day)
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return (day <= __normal_days_in_month[month - 1]);
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const uint32_t *p_months= days_in_month(year, (enum calendar) GREGORIAN);
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return (day <= p_months[1]);
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* Returns the number of days in a month, given
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* a year and a month in the Gregorian calendar.
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* @param Year in Gregorian Proleptic calendar
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* @param Month in date
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uint32_t days_in_gregorian_year_month(uint32_t year, uint32_t month)
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const uint32_t *p_months= days_in_month(year, GREGORIAN);
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return p_months[month - 1];
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* Returns whether the supplied date components are within the
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* range of the UNIX epoch.
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* Times in the range of 1970-01-01T00:00:00 to 2038-01-19T03:14:07
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bool in_unix_epoch_range(uint32_t year,
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if (month == 0 || day == 0)
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if (year < UNIX_EPOCH_MAX_YEARS
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&& year >= UNIX_EPOCH_MIN_YEARS)
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if (year < UNIX_EPOCH_MIN_YEARS)
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if (year == UNIX_EPOCH_MAX_YEARS)
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/* We are on the final day of UNIX Epoch */
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uint32_t seconds= (hour * 60 * 60)
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if (seconds <= ((3 * 60 * 60) + (14 * 60) + 7))
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* Returns the number of the week from a supplied year, month, and
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* date in the Gregorian proleptic calendar. We use strftime() and
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* the %U, %W, and %V format specifiers depending on the value
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* of the sunday_is_first_day_of_week parameter.
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* @param Subject year
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* @param Subject month
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* @param Is sunday the first day of the week?
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* @param Pointer to a uint32_t to hold the resulting year, which
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* may be incremented or decremented depending on flags
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uint32_t week_number_from_gregorian_date(uint32_t year
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, bool sunday_is_first_day_of_week)
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struct tm broken_time;
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broken_time.tm_year= year;
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broken_time.tm_mon= month - 1; /* struct tm has non-ordinal months */
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broken_time.tm_mday= day;
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/* fill out the rest of our tm fields. */
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(void) mktime(&broken_time);
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char result[3]; /* 3 is enough space for a max 2-digit week number */
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size_t result_len= strftime(result
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, (sunday_is_first_day_of_week ? "%U" : "%W")
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return (uint32_t) atoi(result);
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* Returns the ISO week number of a supplied year, month, and
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* date in the Gregorian proleptic calendar. We use strftime() and
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* the %V format specifier to do the calculation, which yields a
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* correct ISO 8601:1988 week number.
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* The final year_out parameter is a pointer to an integer which will
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* be set to the year in which the week belongs, according to ISO8601:1988,
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* which may be different from the Gregorian calendar year.
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* @see http://en.wikipedia.org/wiki/ISO_8601
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* @param Subject year
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* @param Subject month
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* @param Pointer to a uint32_t to hold the resulting year, which
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* may be incremented or decremented depending on flags
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uint32_t iso_week_number_from_gregorian_date(uint32_t year
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struct tm broken_time;
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broken_time.tm_year= year;
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broken_time.tm_mon= month - 1; /* struct tm has non-ordinal months */
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broken_time.tm_mday= day;
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/* fill out the rest of our tm fields. */
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(void) mktime(&broken_time);
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char result[3]; /* 3 is enough space for a max 2-digit week number */
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size_t result_len= strftime(result
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return 0; /* Not valid for ISO8601:1988 */
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uint32_t week_number= (uint32_t) atoi(result);
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* Takes a number in the form [YY]YYMM and converts it into
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* a number of months.
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* @param Period in the form [YY]YYMM
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uint32_t year_month_to_months(uint32_t year_month)
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uint32_t years= year_month / 100;
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if (years < CALENDAR_YY_PART_YEAR)
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else if (years < 100)
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uint32_t months= year_month % 100;
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return (years * 12) + (months - 1);
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* Takes a number of months and converts it to
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* a period in the form YYYYMM.
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* @param Number of months
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uint32_t months_to_year_month(uint32_t months)
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uint32_t years= (months / 12);
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years+= (years < CALENDAR_YY_PART_YEAR) ? 2000 : 1900;
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return (years * 100) + (months % 12) + 1;
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} /* namespace drizzled */