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# test of problems with having (Reported by Mark Rogers)
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drop table if exists t1,t2,t3;
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create table t1 (a int);
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select count(a) as b from t1 where a=0 having b > 0;
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insert into t1 values (null);
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select count(a) as b from t1 where a=0 having b > 0;
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select count(a) as b from t1 where a=0 having b >=0;
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explain extended select count(a) as b from t1 where a=0 having b >=0;
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# Test of problem with HAVING and AVG()
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raw_id int(10) NOT NULL default '0',
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chr_start int(10) NOT NULL default '0',
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chr_end int(10) NOT NULL default '0',
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raw_start int(10) NOT NULL default '0',
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raw_end int(10) NOT NULL default '0',
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raw_ori int(2) NOT NULL default '0'
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INSERT INTO t1 VALUES (469713,1,164123,1,164123,1),(317330,164124,317193,101,153170,1),(469434,317194,375620,101,58527,1),(591816,375621,484273,1,108653,1),(591807,484274,534671,91,50488,1),(318885,534672,649362,101,114791,1),(318728,649363,775520,102,126259,1),(336829,775521,813997,101,38577,1),(317740,813998,953227,101,139330,1),(1,813998,953227,101,139330,1);
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id int(10) unsigned NOT NULL default '0',
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contig_id int(10) unsigned NOT NULL default '0',
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seq_start int(10) NOT NULL default '0',
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seq_end int(10) NOT NULL default '0',
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strand tinyint(2) NOT NULL default '0',
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INSERT INTO t2 VALUES (133195,469713,61327,61384,1),(133196,469713,64113,64387,1),(133197,1,1,1,0),(133197,1,1,1,-2);
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MIN( IF(sgp.raw_ori=1,
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(e.seq_start+sgp.chr_start-sgp.raw_start),
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(sgp.chr_start+sgp.raw_end-e.seq_end))) as start,
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MAX( IF(sgp.raw_ori=1,
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(e.seq_end+sgp.chr_start-sgp.raw_start),
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(sgp.chr_start+sgp.raw_end-e.seq_start))) as end,
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AVG(IF (sgp.raw_ori=1,e.strand,(-e.strand))) as chr_strand
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WHERE sgp.raw_id=e.contig_id
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HAVING chr_strand= -1 and end >= 0
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# Test problem with having and MAX() IS NOT NULL
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CREATE TABLE t1 (Fld1 int(11) default NULL,Fld2 int(11) default NULL);
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INSERT INTO t1 VALUES (1,10),(1,20),(2,NULL),(2,NULL),(3,50);
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select Fld1, max(Fld2) as q from t1 group by Fld1 having q is not null;
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select Fld1, max(Fld2) from t1 group by Fld1 having max(Fld2) is not null;
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select Fld1, max(Fld2) from t1 group by Fld1 having avg(Fld2) is not null;
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select Fld1, max(Fld2) from t1 group by Fld1 having std(Fld2) is not null;
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select Fld1, max(Fld2) from t1 group by Fld1 having variance(Fld2) is not null;
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# Test problem with count(distinct) in having
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create table t1 (id int not null, qty int not null);
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insert into t1 values (1,2),(1,3),(2,4),(2,5);
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select id, sum(qty) as sqty from t1 group by id having sqty>2;
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select sum(qty) as sqty from t1 group by id having count(id) > 0;
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select sum(qty) as sqty from t1 group by id having count(distinct id) > 0;
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# Test case for Bug #4358 Problem with HAVING clause that uses alias from the
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# select list and TEXT field
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`id` bigint(20) NOT NULL default '0',
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`id` bigint(20) NOT NULL default '0',
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`description` varchar(20)
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INSERT INTO t1 VALUES (1, 'test');
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INSERT INTO t2 VALUES (1, 'test');
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`id` bigint(20) NOT NULL default '0',
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`order_id` bigint(20) NOT NULL default '0'
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from t1 a left join t3 b on a.id=b.order_id
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group by a.id, a.description
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having (a.description is not null) and (c=0);
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from t2 a left join t3 b on a.id=b.order_id
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group by a.id, a.description
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having (a.description is not null) and (c=0);
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INSERT INTO t1 VALUES (2, 'test2');
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from t1 a left join t3 b on a.id=b.order_id
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group by a.id, a.description
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having (a.description is not null) and (c=0);
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# Bug #14274: HAVING clause containing only set function
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CREATE TABLE t1 (a int);
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INSERT INTO t1 VALUES (3), (4), (1), (3), (1);
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SELECT SUM(a) FROM t1 GROUP BY a HAVING SUM(a)>0;
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SELECT SUM(a) FROM t1 GROUP BY a HAVING SUM(a);
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# Bug #14927: HAVING clause containing constant false conjunct
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CREATE TABLE t1 (a int);
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INSERT INTO t1 VALUES (1), (2), (1), (3), (2), (1);
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SELECT a FROM t1 GROUP BY a HAVING a > 1;
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SELECT a FROM t1 GROUP BY a HAVING 1 != 1 AND a > 1;
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SELECT 0 AS x, a FROM t1 GROUP BY x,a HAVING x=1 AND a > 1;
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EXPLAIN SELECT a FROM t1 GROUP BY a HAVING 1 != 1 AND a > 1;
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EXPLAIN SELECT 0 AS x, a FROM t1 GROUP BY x,a HAVING x=1 AND a > 1;
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# Bug #29911: HAVING clause depending on constant table and evaluated to false
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CREATE TABLE t1 (a int PRIMARY KEY);
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CREATE TABLE t2 (b int PRIMARY KEY, a int);
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CREATE TABLE t3 (b int, flag int);
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INSERT INTO t1 VALUES (1);
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INSERT INTO t2 VALUES (1,1), (2,1), (3,1);
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INSERT INTO t3(b,flag) VALUES (2, 1);
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FROM t1 INNER JOIN t2 ON t1.a=t2.a LEFT JOIN t3 ON t2.b=t3.b
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GROUP BY t1.a, t2.b HAVING MAX(t3.flag)=0;
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SELECT DISTINCT t1.a, MAX(t3.flag)
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FROM t1 INNER JOIN t2 ON t1.a=t2.a LEFT JOIN t3 ON t2.b=t3.b
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GROUP BY t1.a, t2.b HAVING MAX(t3.flag)=0;
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FROM t1 INNER JOIN t2 ON t1.a=t2.a LEFT JOIN t3 ON t2.b=t3.b
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GROUP BY t1.a, t2.b HAVING MAX(t3.flag)=0;
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# Tests for WL#1972 CORRECT EVALUATION OF COLUMN REFERENCES IN THE HAVING CLAUSE
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# Per the SAP VERI tests and WL#1972, MySQL must ensure that HAVING can
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# correctly evaluate column references from the GROUP BY clause, even if the
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# same references are not also found in the select list.
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# set global sql_mode='ansi';
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# set session sql_mode='ansi';
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create table t1 (col1 int, col2 varchar(5), col_t1 int);
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create table t2 (col1 int, col2 varchar(5), col_t2 int);
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create table t3 (col1 int, col2 varchar(5), col_t3 int);
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insert into t1 values(10,'hello',10);
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insert into t1 values(20,'hello',20);
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insert into t1 values(30,'hello',30);
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insert into t1 values(10,'bye',10);
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insert into t1 values(10,'sam',10);
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insert into t1 values(10,'bob',10);
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insert into t2 select * from t1;
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insert into t3 select * from t1;
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select count(*) from t1 group by col1 having col1 = 10;
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select count(*) as count_col1 from t1 group by col1 having col1 = 10;
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select count(*) as count_col1 from t1 as tmp1 group by col1 having col1 = 10;
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select count(*) from t1 group by col2 having col2 = 'hello';
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select count(*) from t1 group by col2 having col1 = 10;
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select col1 as count_col1 from t1 as tmp1 group by col1 having col1 = 10;
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select col1 as count_col1 from t1 as tmp1 group by col1 having count_col1 = 10;
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select col1 as count_col1 from t1 as tmp1 group by count_col1 having col1 = 10;
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# ANSI: should return SQLSTATE 42000 Syntax error or access violation
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# MySQL: returns 10 - because of GROUP BY name resolution
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select col1 as count_col1 from t1 as tmp1 group by count_col1 having count_col1 = 10;
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# ANSI: should return SQLSTATE 42000 Syntax error or access violation
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# MySQL: returns 10 - because of GROUP BY name resolution
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select col1 as count_col1,col2 from t1 as tmp1 group by col1,col2 having col1 = 10;
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select col1 as count_col1,col2 from t1 as tmp1 group by col1,col2 having count_col1 = 10;
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select col1 as count_col1,col2 from t1 as tmp1 group by col1,col2 having col2 = 'hello';
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select col1 as count_col1,col2 as group_col2 from t1 as tmp1 group by col1,col2 having group_col2 = 'hello';
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select sum(col1) as co12 from t1 group by col2 having col2 10;
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select sum(col1) as co2, count(col2) as cc from t1 group by col1 having col1 =10;
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select t2.col2 from t2 group by t2.col1, t2.col2 having t1.col1 <= 10;
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# queries with nested sub-queries
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# the having column is resolved in the same query
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select t1.col1 from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2 having t2.col1 <= 10);
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select t1.col1 from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2
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(select min(t3.col1) from t3));
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# the having column is resolved in the SELECT clause of the outer query -
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select t1.col1 from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2 having t1.col1 <= 10);
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# the having column is resolved in the SELECT clause of the outer query -
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# error in ANSI, works with MySQL extension
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select t1.col1 as tmp_col from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2 having tmp_col <= 10);
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# the having column is resolved in the FROM clause of the outer query -
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select t1.col1 from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2 having col_t1 <= 10);
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# Item_field must be resolved in the same way as Item_ref
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select sum(col1) from t1
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having (select col_t1 from t2 where col_t1 = col_t2 order by col_t2 limit 1);
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# nested queries with HAVING, inner having column resolved in outer FROM clause
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# the outer having column is not referenced in GROUP BY which results in an error
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select t1.col1 from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2 having col_t1 <= 10)
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# both having columns are resolved in the GROUP clause of the outer query
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select t1.col1 from t1
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(select t2.col2 from t2
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group by t2.col1, t2.col2 having col_t1 <= 10)
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# nested HAVING clauses
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# non-correlated subqueries
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select col_t1, sum(col1) from t1
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having col_t1 > 10 and
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exists (select sum(t2.col1) from t2
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group by t2.col2 having t2.col2 > 'b');
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# correlated subqueries - inner having column 't1.col2' resolves to
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# the outer FROM clause, which cannot be used because the outer query
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select sum(col1) from t1
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having col_t1 in (select sum(t2.col1) from t2
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group by t2.col2, t2.col1 having t2.col1 = t1.col1);
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# correlated subqueries - inner having column 'col_t1' resolves to
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# the outer GROUP clause
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select sum(col1) from t1
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having col_t1 in (select sum(t2.col1) from t2
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group by t2.col2, t2.col1 having t2.col1 = col_t1);
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# queries with joins and ambiguous column names
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select t1.col1, t2.col1 from t1, t2 where t1.col1 = t2.col1
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group by t1.col1, t2.col1 having col1 = 2;
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select t1.col1*10+t2.col1 from t1,t2 where t1.col1=t2.col1
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group by t1.col1, t2.col1 having col1 = 2;
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drop table t1, t2, t3;
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# More queries to test ANSI compatibility
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create table t1 (s1 int);
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insert into t1 values (1),(2),(3);
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select count(*) from t1 group by s1 having s1 is null;
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# prepared statements prints warnings too early
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--disable_ps_protocol
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select s1*0 as s1 from t1 group by s1 having s1 <> 0;
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# ANSI requires: 3 rows
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# MySQL returns: 0 rows - because of GROUP BY name resolution
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select s1*0 from t1 group by s1 having s1 = 0;
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select s1 from t1 group by 1 having 1 = 0;
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select count(s1) from t1 group by s1 having count(1+1)=2;
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# ANSI requires: 3 rows
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# MySQL returns: 0 rows - because of GROUP BY name resolution
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select count(s1) from t1 group by s1 having s1*0=0;
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select * from t1 a, t1 b group by a.s1 having s1 is null;
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# ANSI requires: 0 rows
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# "ERROR 1052 (23000): Column 's1' in having clause is ambiguous"
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# I think the column is ambiguous in ANSI too.
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# select a.s1, b.s1 from t1 a, t1 b group by a.s1 having s1 is null;
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# currently we first check SELECT, thus s1 is ambiguous.
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create table t1 (s1 char character set latin1 collate latin1_german1_ci);
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insert into t1 values ('b'),('y');
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select s1,count(s1) from t1
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group by s1 collate latin1_swedish_ci having s1 = 'y';
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# ANSI requires: 1 row, with count(s1) = 2
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# MySQL returns: 1 row, with count(s1) = 1
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# Bug #15917: unexpected complain for a name in having clause
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# when the server is run on Windows or with --lower-case-table-names=1
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DROP SCHEMA IF EXISTS HU;
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(EMPNUM CHAR(3) NOT NULL UNIQUE,
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(PNUM CHAR(3) NOT NULL UNIQUE,
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INSERT INTO STAFF VALUES ('E1','Alice',12,'Deale');
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INSERT INTO STAFF VALUES ('E2','Betty',10,'Vienna');
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INSERT INTO STAFF VALUES ('E3','Carmen',13,'Vienna');
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INSERT INTO STAFF VALUES ('E4','Don',12,'Deale');
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INSERT INTO STAFF VALUES ('E5','Ed',13,'Akron');
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INSERT INTO PROJ VALUES ('P1','MXSS','Design',10000,'Deale');
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INSERT INTO PROJ VALUES ('P2','CALM','Code',30000,'Vienna');
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INSERT INTO PROJ VALUES ('P3','SDP','Test',30000,'Tampa');
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INSERT INTO PROJ VALUES ('P4','SDP','Design',20000,'Deale');
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INSERT INTO PROJ VALUES ('P5','IRM','Test',10000,'Vienna');
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INSERT INTO PROJ VALUES ('P6','PAYR','Design',50000,'Deale');
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SELECT EMPNUM, GRADE*1000
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FROM HU.STAFF WHERE GRADE * 1000 >
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ANY (SELECT SUM(BUDGET) FROM HU.PROJ
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HAVING HU.PROJ.CITY = HU.STAFF.CITY);
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# Bug#18739: non-standard HAVING extension was allowed in strict ANSI sql mode.
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create table t1(f1 int);
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select f1 from t1 having max(f1)=f1;
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select f1 from t1 group by f1 having max(f1)=f1;
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select f1 from t1 having max(f1)=f1;
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select f1 from t1 group by f1 having max(f1)=f1;
added
removed
mysql-test/t/having.test
